A 6.00 cm x 4.20 cm rectangle lies in the xy-plane
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PART A:
What is the electric flux through the rectangle is E = (120 i^ + 100 k^) N/C?
SOLUTION:
To begin, convert the dimensions to meters so that the problem is in SI units.
x = 0.060 m & y = 0.042 m
The area... Axy = (0.042 m)(0.060 m) → Axy = 0.00252 m2
Normal vector to the xy-plane: Nv = k^
∴ A = Axy⋅Nv →A = (0.00252 m2)k^
Some necessary knowledge needed to solve this problem is the rules for the dot product of unit vectors.
Now, using Gauss's law...
ΦE = ∫E⋅dA
→ ΦE = [(120i^+100k^)N/C]⋅[(0.00252 m2)k^]
ΦE = 0.252 (N⋅m2)/C
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PART B:
What is the electric flux through the rectangle is E = (120 i^ + 100 j^) N/C?
SOLUTION:
Done the same way as in part A...
→ ΦE = [(120i^+100j^)N/C]⋅[(0.00252 m2)k^]
ΦE = 0 (N⋅m2)/C
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