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Thursday, October 23, 2014
29: Problem 29.9
PART A:
What is the direction of the electric field at the dot in the figure?
SOLUTION:
placing the x axis horizontally through the point, it can be figured that V(x) = 10000x
E(x) = -dV(x)/dx so E(x) = -10000 V/m
this means that, based on our imposed axis, the direction of the electric field is to the left
PART B:
What is the magnitude of the electric field at the dot?
SOLUTION:
We already figured this out in the last part, and it is 10000 V/m
Labels:
Chapter 29,
Electric Field,
Electric Potential
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Ok. So, the step is take the integral from 0 to 100? whats the equation for Ex?
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