INTRO: The figure is a graph of Ex
PART A:
What is the potential difference between xi=2.0m and xf=3.0m?
Express your answer to two significant figures and include the appropriate units.
SOLUTION:
To get the potential difference we need to subtract the initial potential from the final potential
ΔV=Vf -Vi
We start out by determining those two values based on the values of Ex that can be seen in the graph
Exi = E2 m = 100 V/m
Exf = E3 m = 200 V/m
ΔV =- ∫xixf E(x)dx
for a function of E(x), y=100x-100
- ∫23 100x-100 dx = -(50x2-100x) |23
= [-50(3)2+100(3)]-[-50(2)2+100(2)] =-450+300+200-200 = -150 V
Hi there what happens when xi is 1.0m and xf is 3.0m?
ReplyDeleteyou integrate the same way that is seen above, but you use the initial and final values that you've been given.
DeleteSee the second to last line of the post? where the 2 & 3 are, you substitute your values, respectively. I'm assuming you know how to integrate, since you're in physics 2, but it really is that simple to just plug your values in.