INTRO:
The magnetic field of an electromagnetic wave in a vacuum is Bz=(2.0μT)sin((9.00×106)x−ωt), where x is in m and t is in s.
Part A:
What is the wave's wavelength?
Express your answer to three significant figures and include the appropriate units.
SOLUTION:
a value for k is given in the formula
k=9.00×106
since λ=2π⋅1/k,
λ = 2π⋅1/9.00×106 = 6.98×10-7 m= 698 nm
Part B:
What is the wave's frequency?
Express your answer to three significant figures and include the appropriate units.
SOLUTION:
using the formula c=fλ, we can easily solve for frequency
f = c/λ = 3.0×108m / 6.98×10-7 m⋅s
f = 4.3×1014 Hz
Part C:
What is the wave's electric field amplitude?
Express your answer to two significant figures and include the appropriate units.
SOLUTION:
E0=cB0
→c(2.0μT)
E0 = 599.6 N/C ≈ 600 V/m
No comments:
Post a Comment